What is the expected output when trying to print a variable defined inside a function that is outside its scope?

When a variable is defined inside a function, its scope is limited to that function. This means that it is not accessible outside the function in which it was declared. When the program attempts to access this variable from outside its scope, it will raise a NameError because Python cannot find a variable with that name in the current scope.

In this scenario, trying to print a variable that has been defined within a function results in the interpreter looking for that variable in the global (outer) scope, where it does not exist. Therefore, you receive a NameError, indicating that the name you've referenced is not defined in that context. This behavior emphasizes the importance of understanding variable scope in Python, where local variables are confined to the functions that define them and cannot be accessed from outside.